# Chapter 1.1, Problem 1PQ

### Calculus: Early Transcendentals

3rd Edition
Jon Rogawski + 1 other
ISBN: 9781464114885

Chapter
Section

### Calculus: Early Transcendentals

3rd Edition
Jon Rogawski + 1 other
ISBN: 9781464114885
To determine

Give an example of numbers $a\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}b$ such that $a|b|$.

Solution:

The condition are true for $a=-2\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}b=1$.

Explanation

Given:

Conditions are $a|b|$.

Calculation:

Let $a=-2\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}b=1$.

Conditions are $a|b|$.

First, substitute the values of $a\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}b$ in the condition $a.

$-2<1$

Now, substitute the values of $a\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}b$ in the condition $|a|>|b|$.

$\begin{array}{c}|a|=|-2|\\ =2\end{array}$

$\begin{array}{c}|b|=|1|\\ =1\end{array}$

So, $2>1$ as $|a|>|b|$.

Hence, the condition are true for $a=-2\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}b=1$.

Conclusion:

By substituting the values, we can check the conditions.

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